Midterm Review: Python Problem Sets 2

Arguments and Functions

Given the following code, what will be the output?

def func(*args, **kwargs):
    print(args)
    print(kwargs)

func(1, 2, 3, a=4, b=5)

Analyze the following code and explain the output:

def func(a, *args, b):
    print(a, args, b)

func(1, 2, 3, 4)

Determine whether the following function definition is valid. If not, explain why:
```
def func(a, b, /, c, *, d):
    return a + b + c + d
```

Is there an error in any of the calls to func? Why? If not, what is the output for each call to func?

def func(a, /, b, *, c):
    return a + b + c

func(1, 2, 3)
func(a=1, b=3, c=3)
func(1, b=2, c=3)

Analyze the following code and explain the behavior:

def func(a, b, /):
    return a + b

print(func(1, 2))
print(func(a=1, b=2))

Determine if the following function works as expected. Explain:

def func(*, a, b):
    return a * b

print(func(a=3, b=4))
print(func(3, 4))

Given the following function, what will be the output of each call? Explain:

def func(a, b, /, c, *, d):
    return a, b, c, d

print(func(1, 2, 3, d=4))
print(func(1, b=2, c=3, d=4))

What is the output of the following code? Explain:

def func(x, y=10):
    return x * y

print(func(5))
print(func(5, 20))

Does the following function definition contain any errors? If so, describe them:
```
def func(a=1, b):
    return a + b
```
Explain the behavior of the following code. Is there any potential pitfall associated with having a keyword argument being assigned a mutable value as a default?
```
def func(a, mylist=[]):
    mylist.append(a)
    return mylist

print(func(1))
print(func(2))
```